## Output from spear5.sas

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```              Spearman's five variables:  Harman, Pp 116,391-392             1
```
` OBS    _TYPE_    _NAME_      TEST1      TEST2      TEST3      TEST4    TEST5`
```  1      CORR     TEST1       1.000       .          .          .          .
2      CORR     TEST2       0.485      1.000       .          .          .
3      CORR     TEST3       0.400      0.397      1.000       .          .
4      CORR     TEST4       0.397      0.397      0.335      1.000       .
5      CORR     TEST5       0.295      0.247      0.275      0.195       1
6      N                  100.000    100.000    100.000    100.000     100```

```              Spearman's five variables:  Harman, Pp 116,391-392             2
Test of hypothesis of one general factor
```
```Initial Factor Method: Maximum Likelihood

Prior Communality Estimates: SMC```
```                   TEST1     TEST2     TEST3     TEST4     TEST5
0.334390  0.320497  0.249282  0.232207  0.123625
```
`      Preliminary Eigenvalues:  Total = 1.74960303  Average = 0.34992061`
```                          1           2           3           4           5
Eigenvalue        2.3117     -0.0078     -0.1481     -0.1619     -0.2442
Difference        2.3195      0.1402      0.0138      0.0823
Proportion        1.3212     -0.0045     -0.0846     -0.0925     -0.1396
Cumulative        1.3212      1.3168      1.2321      1.1396      1.0000
```
`             1 factors will be retained by the NFACTOR criterion.`

`  Iter Criterion    Ridge   Change   Communalities`
```    1    0.00761    0.000  0.16063   0.49502 0.46351 0.34822 0.31795 0.15832
2    0.00759    0.000  0.00429   0.49528 0.46621 0.34393 0.32027 0.15890
3    0.00759    0.000  0.00020   0.49542 0.46625 0.34391 0.32029 0.15870
```
```
Convergence criterion satisfied.```

```       Significance tests based on 100 observations:
```
```          Test of H0: No common factors.
vs HA: At least one common factor.

Chi-square = 87.205   df = 10   Prob>chi**2 = 0.0001

Test of H0: 1 Factors are sufficient.
vs HA: More factors are needed.

Chi-square = 0.727   df = 5   Prob>chi**2 = 0.9815

Chi-square without Bartlett's correction = 0.7510547937
Akaike's Information Criterion = -9.248945206
Schwarz's Bayesian Criterion = -22.27479614
Tucker and Lewis's Reliability Coefficient = 1.1106908068
```
`                        Squared Canonical Correlations`
```                                     FACTOR1
0.752437```

```              Spearman's five variables:  Harman, Pp 116,391-392             3
Test of hypothesis of one general factor
```
```Initial Factor Method: Maximum Likelihood

Eigenvalues of the Weighted Reduced Correlation Matrix:
Total = 3.03938154  Average = 0.60787631```
```                          1           2           3           4           5
Eigenvalue        3.0394      0.0837      0.0216     -0.0203     -0.0850
Difference        2.9557      0.0622      0.0418      0.0647
Proportion        1.0000      0.0275      0.0071     -0.0067     -0.0280
Cumulative        1.0000      1.0275      1.0346      1.0280      1.0000
```
`                                Factor Pattern`
```                           FACTOR1

TEST1      0.70386    Mathematical judgement
TEST2      0.68282    Controlled association
TEST3      0.58643    Literary interpretation
TEST4      0.56594    Selective judgement
TEST5      0.39837    Spelling
```
`                      Variance explained by each factor`
```                                          FACTOR1
Weighted    3.039382
Unweighted  1.784557
```
```               Final Communality Estimates and Variable Weights
Total Communality: Weighted = 3.039382   Unweighted = 1.784557```
```                         TEST1     TEST2     TEST3     TEST4     TEST5
Communality   0.495419  0.466248  0.343901  0.320289  0.158699
Weight        1.981844  1.873521  1.524172  1.471210  1.188635
```
`            Residual Correlations With Uniqueness on the Diagonal`
```                   TEST1     TEST2     TEST3

TEST1      0.50458   0.00439  -0.01277    Mathematical judgement
TEST2      0.00439   0.53375  -0.00343    Controlled association
TEST3     -0.01277  -0.00343   0.65610    Literary interpretation
TEST4     -0.00134   0.01056   0.00311    Selective judgement
TEST5      0.01460  -0.02502   0.04138    Spelling```

```              Spearman's five variables:  Harman, Pp 116,391-392             4
Test of hypothesis of one general factor
```
```Initial Factor Method: Maximum Likelihood

Residual Correlations With Uniqueness on the Diagonal```
```                   TEST4     TEST5

TEST1     -0.00134   0.01460    Mathematical judgement
TEST2      0.01056  -0.02502    Controlled association
TEST3      0.00311   0.04138    Literary interpretation
TEST4      0.67971  -0.03045    Selective judgement
TEST5     -0.03045   0.84130    Spelling
```
```
Root Mean Square Off-diagonal Residuals: Over-all = 0.01948369```

`                   TEST1     TEST2     TEST3     TEST4     TEST5`
```                0.009966  0.013860  0.021777  0.016206  0.029492

```
`                   Partial Correlations Controlling Factors`
```                   TEST1     TEST2     TEST3

TEST1      1.00000   0.00845  -0.02219    Mathematical judgement
TEST2      0.00845   1.00000  -0.00579    Controlled association
TEST3     -0.02219  -0.00579   1.00000    Literary interpretation
TEST4     -0.00229   0.01754   0.00466    Selective judgement
TEST5      0.02241  -0.03733   0.05570    Spelling

TEST4     TEST5

TEST1     -0.00229   0.02241    Mathematical judgement
TEST2      0.01754  -0.03733    Controlled association
TEST3      0.00466   0.05570    Literary interpretation
TEST4      1.00000  -0.04027    Selective judgement
TEST5     -0.04027   1.00000    Spelling
```
```
Root Mean Square Off-diagonal Partials: Over-all = 0.02748151```

`                   TEST1     TEST2     TEST3     TEST4     TEST5`
```                0.016365  0.021250  0.030208  0.022115  0.040683
```